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-6c^2=-60+9c
We move all terms to the left:
-6c^2-(-60+9c)=0
We add all the numbers together, and all the variables
-6c^2-(9c-60)=0
We get rid of parentheses
-6c^2-9c+60=0
a = -6; b = -9; c = +60;
Δ = b2-4ac
Δ = -92-4·(-6)·60
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-39}{2*-6}=\frac{-30}{-12} =2+1/2 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+39}{2*-6}=\frac{48}{-12} =-4 $
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